sql에서 where문 작성시.. 궁금한게있어요.. 정보
개발자 sql에서 where문 작성시.. 궁금한게있어요..본문
select 문에서 'as'로 컬럼이름을 부여한 것을 where 조건에 넣을 수 없는데 다른 방법이 있을까요??
일단은 where문에 as 전의 case문을 다 적었는데...
아래는 제가 코딩하다가 생긴 예입니다..
select
(CASE WHEN PRIOR_DTIME IS NOT NULL THEN
(CASE WHEN DATEPART(DW, PRIOR_DTIME) IN (2,3) THEN DATEDIFF(dd,REQ_DTIME,PRIOR_DTIME) -2
ELSE DATEDIFF(dd,REQ_DTIME,PRIOR_DTIME) END)
WHEN PRIOR_DTIME IS NULL AND COM_DTIME IS NOT NULL THEN
(CASE WHEN DATEPART(DW, COM_DTIME) IN (2,3) THEN DATEDIFF(dd,REQ_DTIME,COM_DTIME) -2
ELSE DATEDIFF(dd,REQ_DTIME,COM_DTIME) END)
ELSE NULL END) as PPPP, --이부분
* FROM CS_CASE
WHERE
-- 1) 안되는 조건 :
PPPP > 2
-- 2) 되는 방법 : case문 똑같이 다 써주기..
(CASE WHEN PRIOR_DTIME IS NOT NULL THEN
(CASE WHEN DATEPART(DW, PRIOR_DTIME) IN (2,3) THEN DATEDIFF(dd,REQ_DTIME,PRIOR_DTIME) -2 ELSE DATEDIFF(dd,REQ_DTIME,PRIOR_DTIME) END)
WHEN PRIOR_DTIME IS NULL AND COM_DTIME IS NOT NULL THEN
(CASE WHEN DATEPART(DW, COM_DTIME) IN (2,3) THEN DATEDIFF(dd,REQ_DTIME,COM_DTIME) -2 ELSE DATEDIFF(dd,REQ_DTIME,COM_DTIME) END)
ELSE NULL END) >2
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select
(CASE WHEN PRIOR_DTIME IS NOT NULL THEN
(CASE WHEN DATEPART(DW, PRIOR_DTIME) IN (2,3) THEN DATEDIFF(dd,REQ_DTIME,PRIOR_DTIME) -2
ELSE DATEDIFF(dd,REQ_DTIME,PRIOR_DTIME) END)
WHEN PRIOR_DTIME IS NULL AND COM_DTIME IS NOT NULL THEN
(CASE WHEN DATEPART(DW, COM_DTIME) IN (2,3) THEN DATEDIFF(dd,REQ_DTIME,COM_DTIME) -2
ELSE DATEDIFF(dd,REQ_DTIME,COM_DTIME) END)
ELSE NULL END) as PPPP,
* FROM CS_CASE
) FROM TMP WHERE PPPP > 2